Redox Reactions
Redox Reactions in terms of Electron Transfer Reactions
Balancing of redox reaction :
Ion electron (or) half reaction :
Split the reaction into two half reaction.
| LHR | RHR |
| C_{2}O_4^{2-} \rightarrow CO_{2} | MnO_4^{-} \rightarrow Mn^{+2} |
| C_{2}O_4^{-2} \rightarrow 2CO_{2} | MnO_4^{-} \rightarrow Mn^{+2} + 4H_{2}O |
| C_{2}O_4^{2-} \rightarrow 2CO_{2} | MnO_4^{-} + 8H^{+} \rightarrow Mn^{+2} + 4H_{2}O |
| C_{2}O_4^{-2} \rightarrow 2CO_{2} + 2e^{-} | MnO_4^{-} + 8H^{+} + 5e^{-}\rightarrow Mn^{+2} + 4H_{2}O |
| 5C_{2}O_4^{2-} \rightarrow 10CO_{2} + 10e^{-} | 2MnO_4^{-} + 16H^{+} + 10e^{-}\rightarrow 2Mn^{+2} + 8H_{2}O |
Finally 2MnO_4^{-} + 5C_{2}O_4^{-2} + 16H^{+} \rightarrow 2Mn^{+2} + 10CO_{2} + 8H_{2}O
II nd method (Competitive purpose)
Adjust the coefficient
2MnO_4^{-} + 5C_{2}O_4^{-2} \rightarrow Mn^{+2} + CO_{2}
Balance the atoms except (O2 and H2)
2MnO_4^{-} + 5C_{2}O_4^{-2} \rightarrow 2Mn^{+2} + 10CO_{2}
Balancing O2 molecule by water (H2O)
2MnO_4^{-} + 5C_{2}O_4^{-} \rightarrow 2Mn^{+2} + 10CO_{2} + 8H_{2}O
Balancing H+ ions
2MnO_4^{-} + 5C_{2}O_4^{-} + 16H^{+} \rightarrow 2Mn^{+2} + 10CO_{2} + 8H_{2}O
View the Topic in this Video from 0:40 to 49:38
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